(4x^2-5x-12)-(3x^2-5x+4)=

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Solution for (4x^2-5x-12)-(3x^2-5x+4)= equation:


Simplifying
(4x2 + -5x + -12) + -1(3x2 + -5x + 4) = 0

Reorder the terms:
(-12 + -5x + 4x2) + -1(3x2 + -5x + 4) = 0

Remove parenthesis around (-12 + -5x + 4x2)
-12 + -5x + 4x2 + -1(3x2 + -5x + 4) = 0

Reorder the terms:
-12 + -5x + 4x2 + -1(4 + -5x + 3x2) = 0
-12 + -5x + 4x2 + (4 * -1 + -5x * -1 + 3x2 * -1) = 0
-12 + -5x + 4x2 + (-4 + 5x + -3x2) = 0

Reorder the terms:
-12 + -4 + -5x + 5x + 4x2 + -3x2 = 0

Combine like terms: -12 + -4 = -16
-16 + -5x + 5x + 4x2 + -3x2 = 0

Combine like terms: -5x + 5x = 0
-16 + 0 + 4x2 + -3x2 = 0
-16 + 4x2 + -3x2 = 0

Combine like terms: 4x2 + -3x2 = 1x2
-16 + 1x2 = 0

Solving
-16 + 1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 1x2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 1x2 = 0 + 16
1x2 = 0 + 16

Combine like terms: 0 + 16 = 16
1x2 = 16

Divide each side by '1'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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